25n^2=225

Solution for 25n^2=225 equation:

25n^2=225

We move all terms to the left:

25n^2-(225)=0

a = 25; b = 0; c = -225;
Δ = b2-4ac
Δ = 02-4·25·(-225)
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{22500}=150$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-150}{2*25}=\frac{-150}{50}
=-3
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+150}{2*25}=\frac{150}{50}
=3
$